MHT CET · Physics · Current Electricity
The length of a potentiometer wire is 'L'. A cell of e.m.f. 'E' is balanced at a length \(\frac{L}{4}\) from the positive end of the wire. If the length of the original wire is increased by \(\frac{L}{3}\), then using the same cell null point is obtained at
- A \(\frac{L}{4}\)
- B \(\frac{L}{3}\)
- C \(\frac{L}{2}\)
- D \(\frac{3 \mathrm{~L}}{4}\)
Answer & Solution
Correct Answer
(B) \(\frac{L}{3}\)
Step-by-step Solution
Detailed explanation
\(E = k \frac{L}{4}\) \(L' = L + \frac{L}{3} = \frac{4L}{3}\)
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