MHT CET · Physics · Current Electricity
The length of a potentiometer wire is 'L'. A cell of e.m.f. 'E' is balanced at a length \(\frac{\mathrm{L}^{\prime}}{5}\) from the positive end of the wire. If the length of the wire is increased by \(\frac{\mathrm{L}}{2}\),
at what distance will the same cell give a balance point? '
- A \(\frac{5 \mathrm{~L}}{12}\)
- B \(\frac{2 \mathrm{~L}}{15}\)
- C \(\frac{4 \mathrm{~L}}{15}\)
- D \(\frac{3 \mathrm{~L}}{10}\)
Answer & Solution
Correct Answer
(D) \(\frac{3 \mathrm{~L}}{10}\)
Step-by-step Solution
Detailed explanation
If the length of potentiometer wire is increased by \(\frac{L}{2}\), the balancing length will also increase in the same proportion. Hence from \(\frac{L}{5}\) it will increase by \(\frac{1}{2}\left(\frac{L}{5}\right)\) and become \(\frac{L}{5}+\frac{L}{10}=\frac{3 L}{10}\)
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