MHT CET · Physics · Alternating Current
The instantaneous values of current and voltage in an AC circuit are given by \(I=6 \sin \left(100 \pi t+\frac{\pi}{4}\right)\) and \(V=5 \sin \left(100 \pi t-\frac{\pi}{4}\right)\), then
- A voltage leads the current by \(45^{\circ}\)
- B current leads the voltage by \(45^{\circ}\)
- C voltage leads the current by \(90^{\circ}\)
- D current leads the voltage by \(90^{\circ}\)
Answer & Solution
Correct Answer
(D) current leads the voltage by \(90^{\circ}\)
Step-by-step Solution
Detailed explanation
The phase difference between instantaneous value of \(I\) and \(V\) is
\(\Delta \phi=\frac{\pi}{4}-\left(-\frac{\pi}{4}\right)=\frac{\pi}{2}\)
Hence, the current leads voltage by \(90^{\circ}\)
\(\Delta \phi=\frac{\pi}{4}-\left(-\frac{\pi}{4}\right)=\frac{\pi}{2}\)
Hence, the current leads voltage by \(90^{\circ}\)
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