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MHT CET · Physics · Semiconductors

The input signal given to C.E. amplifier having a voltage gain of 126 is \(V_i=2 \cos \left(12 t+\frac{\pi}{3}\right)\). The corresponding output signal will be

  1. A \(252 \cos \left(12 \mathrm{t}+\frac{4 \pi}{3}\right)\)
  2. B \(252 \cos \left(12 t+\frac{\pi}{3}\right)\)
  3. C \(63 \cos \left(12 t+\frac{2 \pi}{3}\right)\)
  4. D \(2 \cos \left(12 t+\frac{5 \pi}{3}\right)\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(252 \cos \left(12 \mathrm{t}+\frac{4 \pi}{3}\right)\)

Step-by-step Solution

Detailed explanation

\(\begin{aligned}
& V_i=2 \cos \left(12 t+\frac{\pi}{3}\right) ...(given)\\
& \text { Voltage gain }=\frac{V_0}{V_i} \\
& V_0=126 \times 2 \cos \left(12 t+\frac{\pi}{3}\right) \\
& \quad=252 \cos \left(12 t+\frac{\pi}{3}\right)
\end{aligned}\)
In CE amplifier, \(\mathrm{V}_0\) and \(\mathrm{V}_{\mathrm{i}}\) have a phase difference of \(\pi\) between them.
\(\begin{aligned}
V_0 & =252 \cos \left(12 t+\frac{\pi}{3}+\pi\right) \\
& =252 \cos \left(12 t+\frac{4 \pi}{3}\right)
\end{aligned}\)
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