MHT CET · Physics · Semiconductors
The input signal given to C.E. amplifier having a voltage gain of 126 is \(V_i=2 \cos \left(12 t+\frac{\pi}{3}\right)\). The corresponding output signal will be
- A \(252 \cos \left(12 \mathrm{t}+\frac{4 \pi}{3}\right)\)
- B \(252 \cos \left(12 t+\frac{\pi}{3}\right)\)
- C \(63 \cos \left(12 t+\frac{2 \pi}{3}\right)\)
- D \(2 \cos \left(12 t+\frac{5 \pi}{3}\right)\)
Answer & Solution
Correct Answer
(A) \(252 \cos \left(12 \mathrm{t}+\frac{4 \pi}{3}\right)\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& V_i=2 \cos \left(12 t+\frac{\pi}{3}\right) ...(given)\\
& \text { Voltage gain }=\frac{V_0}{V_i} \\
& V_0=126 \times 2 \cos \left(12 t+\frac{\pi}{3}\right) \\
& \quad=252 \cos \left(12 t+\frac{\pi}{3}\right)
\end{aligned}\)
In CE amplifier, \(\mathrm{V}_0\) and \(\mathrm{V}_{\mathrm{i}}\) have a phase difference of \(\pi\) between them.
\(\begin{aligned}
V_0 & =252 \cos \left(12 t+\frac{\pi}{3}+\pi\right) \\
& =252 \cos \left(12 t+\frac{4 \pi}{3}\right)
\end{aligned}\)
& V_i=2 \cos \left(12 t+\frac{\pi}{3}\right) ...(given)\\
& \text { Voltage gain }=\frac{V_0}{V_i} \\
& V_0=126 \times 2 \cos \left(12 t+\frac{\pi}{3}\right) \\
& \quad=252 \cos \left(12 t+\frac{\pi}{3}\right)
\end{aligned}\)
In CE amplifier, \(\mathrm{V}_0\) and \(\mathrm{V}_{\mathrm{i}}\) have a phase difference of \(\pi\) between them.
\(\begin{aligned}
V_0 & =252 \cos \left(12 t+\frac{\pi}{3}+\pi\right) \\
& =252 \cos \left(12 t+\frac{4 \pi}{3}\right)
\end{aligned}\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Physics
- In the arrangement shown in the figure, the mass ' m ' will ascend with an acceleration (consider pully and rope are massless) ( \(g=\) acceleration due to gravity)
MHT CET 2025 Medium - A force \((5 \hat{\imath}-2 \hat{\jmath}+3 \hat{k}) \mathrm{N}\) acts on a body of mass \(2 \mathrm{~kg}\) and displaces it from \((3 \hat{\imath}+2 \hat{\jmath}-\hat{k})$$\mathrm{m}\) to \((6 \hat{\imath}-\hat{\jmath}+4 \hat{k}) \mathrm{m} .\) The work done isMHT CET 2020 Easy
- A glass tube of uniform cross-section is connected to a tap with a rubber tube. The tap is opened slowly. Initially the flow of water in the tube is streamline. The speed of flow of water to convert it into a turbulent flow is
[radius of tube \(=1 \mathrm{~cm}, \eta=1 \times 10^{-3} \frac{\mathrm{Ns}}{\mathrm{m}^2}, \mathrm{R}_{\mathrm{n}}=2500\) and density of water \(=10^3 \mathrm{~kg} / \mathrm{m}^3\) ]MHT CET 2021 Medium - The weight suspended from a spring oscillates up and down. The acceleration of weight will be zero atMHT CET 2020 Easy
- A concave mirror of focal length ' \(f\) ' produces an image ' \(n\) ' time the size of the object. If the image is real, then the distance of the object from the mirror isMHT CET 2024 Medium
- An inductance coil has a resistance of \(80 \Omega\). When on AC signal of frequency 480 Hz is applied to the coil, the voltage leads the current by \(45^{\circ}\). The inductance of the coil in henry is \(\left[\sin 45^{\circ}=\cos 45^{\circ}=1 / \sqrt{2}\right]\)MHT CET 2024 Medium
More PYQs from MHT CET
- A buffer solution is prepared by mixing 0.01 M HCN and 0.02 MNaCN . If \(\mathrm{K}_{\mathrm{a}}\) for HCN is \(6.6 \times 10^{-10}\), what is the concentration of \(\mathrm{H}^{+}\)ions in solution?MHT CET 2024 Hard
- \(\int_0^\pi \frac{\mathrm{d} x}{4+3 \cos x}=\)MHT CET 2023 Hard
- Electron in Hydrogen atom first jumps from third excited state to second excited
state and then from second excited state to first excited state. The ratio of the
wavelengths \(\lambda_{1}: \lambda_{2}\) emitted in the two cases respectively isMHT CET 2020 Easy - For the reaction, \(\mathrm{C}_2 \mathrm{H}_2 \mathrm{OH}(l)+30_{2(\mathrm{~g})} \rightarrow 2 \mathrm{C}_2 \mathrm{O}(l) \Delta \mathrm{U}\) is the heat of reaction at constant volume. Then heat of reaction at constant pressure isMHT CET 2022 Medium
- Identify the product ' B ' in the following sequence of reactions.
Methylpropanoate \(\underset{\text { dil. } \mathrm{NaOH}}{\stackrel{\Delta}{\longrightarrow}} \mathrm{A} \xrightarrow[\text { Conc. } \mathrm{HCl}]{\mathrm{H}^{+}} \mathrm{B}\)MHT CET 2025 Medium - If \(\tan \theta=\frac{\sin \alpha-\cos \alpha}{\sin \alpha+\cos \alpha}, 0 \leq \alpha \leq \frac{\pi}{2}\), then the value of \(\cos 2 \theta\) isMHT CET 2023 Easy