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MHT CET · Physics · Thermodynamics

The initial pressure and volume of a gas is ' \(\mathrm{P}\) ' and ' \(\mathrm{V}\) ' respectively. First by isothermal process gas is expanded to volume ' \(9 \mathrm{~V}\) ' and then by adiabatic process its volume is compressed to ' \(\mathrm{V}\) ' then its final pressure is (Ratio of specific heat at constant pressure to constant volume \(=\frac{3}{2}\) )

  1. A \(6 \mathrm{~A}\)
  2. B 27P
  3. C 3P
  4. D 9P
Verified Solution

Answer & Solution

Correct Answer

(C) 3P

Step-by-step Solution

Detailed explanation

\(\frac{C_p}{C_v}=\frac{3}{2}\)
Case I:
Isothermal process
\(
\begin{aligned}
& \mathrm{P}_1 \mathrm{~V}_1=\mathrm{P}_2 \mathrm{~V}_2 \\
& \mathrm{PV}=\mathrm{P}_2 \times 9 \mathrm{~V} \\
& \therefore \mathrm{P}_2=\frac{\mathrm{P}}{9}
\end{aligned}
\)
Case II: Adiabatic process
\(
\begin{aligned}
& \mathrm{P}_2 \mathrm{~V}_2^\gamma=\mathrm{P}_3 \mathrm{~V}_3^\gamma \\
& \frac{\mathrm{P}}{9}(9 \mathrm{~V})^\gamma=\mathrm{P}_3(\mathrm{~V})^\gamma \\
& \mathrm{P}_3=\left(\frac{\mathrm{P}}{9}\right) 9^\gamma=\left(\frac{\mathrm{P}}{9}\right) 9^{3 / 2}=\frac{\mathrm{P}}{9} \times 27=3 \mathrm{P}
\end{aligned}
\)