MHT CET · Physics · Mechanical Properties of Solids
The increase in pressure required to decrease the \(200 \mathrm{~L}\) volume of a liquid by \(0.008 \%\) in \(\mathrm{kPa}\) is (Bulk modulus of the liquid \(=2100 \mathrm{MPa}\) is )
- A \(8.4\)
- B 84
- C \(92.4\)
- D 168
Answer & Solution
Correct Answer
(B) 84
Step-by-step Solution
Detailed explanation
Bulk modulus \(K=\frac{\Delta p}{\Delta V} \cdot V\)
\(\begin{array}{l}\Delta p=\frac{K \Delta V}{V} \\\Delta p=\frac{2100 \times 10^{6} \times 0.008}{200}\end{array}\)
\(\begin{array}{l}\Delta p=\frac{K \Delta V}{V} \\\Delta p=\frac{2100 \times 10^{6} \times 0.008}{200}\end{array}\)
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