MHT CET · Physics · Atomic Physics
The ground state energy of hydrogen atom is \(-13 \cdot 6 \mathrm{eV}\). The kinetic and potential energy of the electron in the second excited state is respectively
- A \(+3 \cdot 02 \mathrm{eV},-1 \cdot 51 \mathrm{eV}\)
- B \(1 \cdot 51 \mathrm{eV},-3 \cdot 02 \mathrm{eV}\)
- C \(-1 \cdot 51 \mathrm{eV},+3 \cdot 02 \mathrm{eV}\)
- D \(+3 \cdot 02 \mathrm{eV},+1 \cdot 51 \mathrm{eV}\)
Answer & Solution
Correct Answer
(B) \(1 \cdot 51 \mathrm{eV},-3 \cdot 02 \mathrm{eV}\)
Step-by-step Solution
Detailed explanation
(D)
For second excited state \(n=3\)
Total energy in the third orbit
\(E_{3}=\frac{-13.6}{9} \mathrm{eV}=-1.51 \mathrm{eV}\)
K.E. \(=-\) T.E. \(\quad=1.51 \mathrm{eV}\)
P.E. \(=2\).T.E. \(=-3.32 \mathrm{eV}\)
For second excited state \(n=3\)
Total energy in the third orbit
\(E_{3}=\frac{-13.6}{9} \mathrm{eV}=-1.51 \mathrm{eV}\)
K.E. \(=-\) T.E. \(\quad=1.51 \mathrm{eV}\)
P.E. \(=2\).T.E. \(=-3.32 \mathrm{eV}\)
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