MHT CET · Physics · Dual Nature of Matter
The graph shows the variation of photocurrent with anode potential for four different radiations. Let \(I_a, I_b, I_c\) and \(I_d\) are intensities and \(f_a, f_b, f_c\) and \(f_d\) be the frequencies for the curves \(a, b, c\) and \(d\) respectively, then
- A \(\mathrm{f}_{\mathrm{b}}>\mathrm{f}_{\mathrm{a}}, \mathrm{f}_{\mathrm{b}}=\mathrm{f}_{\mathrm{c}}, \mathrm{I}_{\mathrm{c}}=\mathrm{I}_{\mathrm{d}}\)
- B \(\mathrm{f}_{\mathrm{b}}=\mathrm{f}_{\mathrm{a}}, \mathrm{f}_{\mathrm{b}}>\mathrm{f}_{\mathrm{c}}, \mathrm{I}_{\mathrm{c}}>\mathrm{I}_{\mathrm{d}}\)
- C \(\mathrm{f}_{\mathrm{b}} < \mathrm{f}_{\mathrm{a}}, \mathrm{f}_{\mathrm{b}} < \mathrm{f}_{\mathrm{c}}, \mathrm{I}_{\mathrm{c}} < \mathrm{I}_{\mathrm{d}}\)
- D \(\mathrm{f}_{\mathrm{b}} \leqslant \mathrm{f}_{\mathrm{a}}, \mathrm{f}_{\mathrm{b}}>\mathrm{f}_{\mathrm{c}}, \mathrm{I}_{\mathrm{c}}=\mathrm{I}_{\mathrm{d}}\)
Answer & Solution
Correct Answer
(A) \(\mathrm{f}_{\mathrm{b}}>\mathrm{f}_{\mathrm{a}}, \mathrm{f}_{\mathrm{b}}=\mathrm{f}_{\mathrm{c}}, \mathrm{I}_{\mathrm{c}}=\mathrm{I}_{\mathrm{d}}\)
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