MHT CET · Physics · Dual Nature of Matter
The graph of stopping potential ' \(\mathrm{V}_{\mathrm{s}}\) ' against frequency ' \(v\) ' of incident radiation is plotted for two different metals ' X ' and ' Y ' as shown in graph. ' \(\phi_{\mathrm{x}}\) ' and ' \(\phi_{\mathrm{y}}\) ' are work functions of ' x ' and ' \(Y\) ', respectively then
- A \(\phi_x=\phi_y\)
- B \(\phi_x \lt \phi_y\)
- C \(\phi_x\gt\phi_y\)
- D \(\phi_x=\phi_y=0\)
Answer & Solution
Correct Answer
(B) \(\phi_x \lt \phi_y\)
Step-by-step Solution
Detailed explanation
We know
\(\phi=h v_0 \quad \Rightarrow \phi \propto v_0\)
Also,
\(\begin{aligned}
& v_0 \lt v_0^{\prime} \\
& \therefore \phi_x \lt \phi_y ..(From graph)
\end{aligned}\)
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