MHT CET · Physics · Alternating Current
The frequency at resonance for the circuit is
- A \(\frac{1}{4 \pi \sqrt{\mathrm{LC}}}\)
- B \(\frac{1}{2 \pi \sqrt{\mathrm{LC}}}\)
- C \(\frac{1}{\pi \sqrt{\mathrm{LC}}}\)
- D \(\frac{2}{\pi \sqrt{\mathrm{LC}}}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2 \pi \sqrt{\mathrm{LC}}}\)
Step-by-step Solution
Detailed explanation
\(f = \frac{1}{2 \pi \sqrt{LC}}\)
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