MHT CET · Physics · Mechanical Properties of Fluids
The force required to take away a flat circular plate of radius 2 \(\mathrm{cm}\) from the surface of water is \(\left[\right.\) Surface tension of water \(\left.=70 \times 10^{-3} \mathrm{Nm}^{-1}, \pi=\frac{22}{7}\right]\)
- A \(4.4 \times 10^{-4} \mathrm{~N}\)
- B \(8.8 \times 10^{-3} \mathrm{~N}\)
- C \(6.6 \times 10^{-4} \mathrm{~N}\)
- D \(11 \times 10^{-3} \mathrm{~N}\)
Answer & Solution
Correct Answer
(B) \(8.8 \times 10^{-3} \mathrm{~N}\)
Step-by-step Solution
Detailed explanation
The force required to take away circular plate due to surface tension
\(
\begin{aligned}
& F=2 \pi r \mathrm{~T} \\
& =2 \times \frac{22}{7} \times 2 \times 10^{-2} \times 70 \times 10^{-3} \\
& =8.8 \times 10^{-3} \mathrm{~N}
\end{aligned}
\)
\(
\begin{aligned}
& F=2 \pi r \mathrm{~T} \\
& =2 \times \frac{22}{7} \times 2 \times 10^{-2} \times 70 \times 10^{-3} \\
& =8.8 \times 10^{-3} \mathrm{~N}
\end{aligned}
\)
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