MHT CET · Physics · Laws of Motion
The figure shows two masses ' m ' and ' M ' connected by a light string that passes through a small hole 'O' at the centre of the table. Mass ' m ' is moved round in a horizontal circle with 'O' as the centre. The frequency with which ' m ' should be revolved so that ' M ' remains stationary is
(g = gravitational acceleration)
- A \(\frac{1}{\pi} \sqrt{\frac{\mathrm{ML}}{\mathrm{mg}}}\)
- B \(\frac{1}{2 \pi} \sqrt{\frac{\mathrm{Mg}}{\mathrm{mL}}}\)
- C \(\frac{1}{\pi} \sqrt{\frac{\mathrm{Mg}}{\mathrm{mL}}}\)
- D \(\frac{1}{2 \pi} \sqrt{\frac{\mathrm{ML}}{\mathrm{mg}}}\)
Answer & Solution
Correct Answer
(B) \(\frac{1}{2 \pi} \sqrt{\frac{\mathrm{Mg}}{\mathrm{mL}}}\)
Step-by-step Solution
Detailed explanation
\(T = Mg\) \(T = mL\omega^2\)
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