MHT CET · Physics · Ray Optics
The figure shows equiconvex lens of focal length ' \(\mathrm{f}\) '. If the lens is cut along \(\mathrm{AB}\), the
focal length of each half will be


- A \(2 \mathrm{f}\)
- B \(\mathrm{f}\)
- C \(3 \mathrm{f}\)
- D \(4 \mathrm{f}\)
Answer & Solution
Correct Answer
(A) \(2 \mathrm{f}\)
Step-by-step Solution
Detailed explanation
\( \frac{1}{\mathrm{f}} = (\mu - 1) \left( \frac{1}{\mathrm{R}} - \frac{1}{-\mathrm{R}} \right) = (\mu - 1) \frac{2}{\mathrm{R}} \) \( \frac{1}{\mathrm{f}'} = (\mu - 1) \left( \frac{1}{\mathrm{R}} - \frac{1}{\infty} \right) = (\mu - 1) \frac{1}{\mathrm{R}} \)
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