MHT CET · Physics · Waves and Sound
The equations of two waves are given as
\(\begin{aligned}
& \mathrm{y}_1=\mathrm{asin}\left(\omega \mathrm{t}+\phi_1\right) \
& \mathrm{y}_2=\operatorname{asin}\left(\omega \mathrm{t}+\phi_2\right)
\end{aligned}\)
If amplitude and time period of resultant wave is same as the individual waves, then \(\left(\phi_1-\phi_2\right)\) is
- A \(\cos ^{-1}\left(\frac{-1}{2}\right)\)
- B \(\cos ^{-1}\left(\frac{-1}{4}\right)\)
- C \(\cos ^{-1}\left(-\frac{1}{6}\right)\)
- D \(\cos ^{-1}\left(-\frac{1}{8}\right)\)
Answer & Solution
Correct Answer
(A) \(\cos ^{-1}\left(\frac{-1}{2}\right)\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned}
& \mathrm{y}_1=\mathrm{a} \sin \left(\omega \mathrm{t}+\phi_1\right) \\
& \mathrm{y}_2=\operatorname{asin}\left(\omega \mathrm{t}+\phi_2\right)
...(i)\end{aligned}\)
Superposition of two waves is given by
\(a^2=a_1^2+a_2^2+2 a_1 a_2 \cos \phi\)
...(ii)
Here, \(\phi=\phi_1-\phi_2\) and \(a_1=a_2=a\)
Substituting these values in equation (i), we get,
\(\begin{aligned}
& \cos \left(\phi_1-\phi_2\right)=-\frac{1}{2} \\
\therefore \quad & \left(\phi_1-\phi_2\right)=\cos ^{-1}\left(\frac{-1}{2}\right)
\end{aligned}\)
& \mathrm{y}_1=\mathrm{a} \sin \left(\omega \mathrm{t}+\phi_1\right) \\
& \mathrm{y}_2=\operatorname{asin}\left(\omega \mathrm{t}+\phi_2\right)
...(i)\end{aligned}\)
Superposition of two waves is given by
\(a^2=a_1^2+a_2^2+2 a_1 a_2 \cos \phi\)
...(ii)
Here, \(\phi=\phi_1-\phi_2\) and \(a_1=a_2=a\)
Substituting these values in equation (i), we get,
\(\begin{aligned}
& \cos \left(\phi_1-\phi_2\right)=-\frac{1}{2} \\
\therefore \quad & \left(\phi_1-\phi_2\right)=\cos ^{-1}\left(\frac{-1}{2}\right)
\end{aligned}\)
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