MHT CET · Physics · Dual Nature of Matter
The energy that should be added to an electron to reduce its de-Broglie wavelength from \(\lambda\) to \(\frac{\lambda}{2}\) is n times the initial energy. The value of ' n ' is
- A 4
- B 3
- C 2
- D 1
Answer & Solution
Correct Answer
(B) 3
Step-by-step Solution
Detailed explanation
\(E = \frac{p^2}{2m}\), \(\lambda = \frac{h}{p}\) \(\implies\) \(p = \frac{h}{\lambda}\) \(E = \frac{(h/\lambda)^2}{2m} = \frac{h^2}{2m\lambda^2}\)
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