MHT CET · Physics · Mechanical Properties of Fluids
The energy needed for breaking a liquid drop of radius ' \(R\) ' into 216 droplets, each of radius ' \(r\) ' is ' \(x\) ' times TR \({ }^2\). The value of ' \(x\) ' is [ \(\mathrm{T}=\) surface tension of the liquid]
- A \(4 \pi\)
- B \(12 \pi\)
- C \(180 \pi\)
- D \(20 \pi\)
Answer & Solution
Correct Answer
(D) \(20 \pi\)
Step-by-step Solution
Detailed explanation
\( \frac{4}{3}\pi R^3 = 216 \cdot \frac{4}{3}\pi r^3 \) \( R^3 = 216 r^3 \implies R = 6r \)
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