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MHT CET · Physics · Mechanical Properties of Fluids

The energy needed for breaking a liquid drop of radius ' \(R\) ' into 216 droplets, each of radius ' \(r\) ' is ' \(x\) ' times TR \({ }^2\). The value of ' \(x\) ' is [ \(\mathrm{T}=\) surface tension of the liquid]

  1. A \(4 \pi\)
  2. B \(12 \pi\)
  3. C \(180 \pi\)
  4. D \(20 \pi\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(20 \pi\)

Step-by-step Solution

Detailed explanation

\( \frac{4}{3}\pi R^3 = 216 \cdot \frac{4}{3}\pi r^3 \) \( R^3 = 216 r^3 \implies R = 6r \)