MHT CET · Physics · Electrostatics
The electric field intensity near a conducting surface having uniform surface charge density ' \(\sigma\) ' is given by ( \(\epsilon_0=\) permittivity of free space)
- A \(\frac{\sigma}{\epsilon_0}\) and is parallel to the surface
- B \(\frac{2 \sigma}{\epsilon_0}\) and is parallel to the surface
- C \(\frac{\sigma}{\epsilon_0}\) and is normal to the surface
- D \(\frac{2 \sigma}{\epsilon_0}\) and is normal to the surface
Answer & Solution
Correct Answer
(C) \(\frac{\sigma}{\epsilon_0}\) and is normal to the surface
Step-by-step Solution
Detailed explanation
\( E = \frac{\sigma}{\epsilon_0} \) and is normal to the surface.
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