MHT CET · Physics · Waves and Sound
The distance between two consecutive points with phase difference of \(45^{\circ}\) in a wave of frequency 300 Hz is 4.0 m . The velocity of the travelling wave is (in \(\mathrm{km} / \mathrm{s}\) )
- A 1.6
- B 3.6
- C 4.8
- D 9.6
Answer & Solution
Correct Answer
(D) 9.6
Step-by-step Solution
Detailed explanation
\( \Delta\phi = \frac{2\pi}{\lambda} \Delta x \) \( \frac{45^{\circ}\pi}{180^{\circ}} = \frac{2\pi}{\lambda}(4.0 \text{ m}) \)
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