ExamBro
ExamBro
MHT CET · Physics · Oscillations

The displacement of particle in S.H.M. is \(x=A \cos (\omega t+\pi / 6)\). Its speed will be maximum at time \(\left(\operatorname{Sin} 90^{\circ}=1\right)\)

  1. A \(\frac{\pi}{3 \omega} s\)
  2. B \(\frac{\pi}{2 \omega} s\)
  3. C \(\frac{\pi}{\omega} s\)
  4. D \(\frac{\pi}{4 \omega} s\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(\frac{\pi}{3 \omega} s\)

Step-by-step Solution

Detailed explanation

\(v = \frac{d}{dt} (A \cos (\omega t+\pi / 6)) = -A \omega \sin (\omega t+\pi / 6)\) \(|v|_{max}\) when \(\sin (\omega t+\pi / 6) = \pm 1\)