MHT CET · Physics · Gravitation
The depth from the surface of the earth of radius \(\mathrm{R}\), at which acceleration due to gravity will be \(60 \%\) of the value of the value on the earth surface is
- A \(\frac{2 \mathrm{R}}{3}\)
- B \(\frac{2 R}{5}\)
- C \(\frac{3 R}{5}\)
- D \(\frac{5 \mathrm{R}}{3}\)
Answer & Solution
Correct Answer
(B) \(\frac{2 R}{5}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & g^{\prime}=g\left(1-\frac{d}{R}\right) \\ & g^{\prime}=0.6 g \\ & \therefore 0.6=1-\frac{d}{R} \\ & \therefore \frac{d}{R}=1-0.6=0.4=\frac{2}{5} \\ & \therefore d=\frac{2}{5} R\end{aligned}\)
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