MHT CET · Physics · Dual Nature of Matter
The de-Broglie wavelength \((\lambda)\) of a particle is related to its kinetic energy \((\mathrm{E})\) as
- A \(\lambda \propto \mathrm{E}\)
- B \(\lambda \propto \mathrm{E}^{-1}\)
- C \(\lambda \propto \mathrm{E}^{\frac{1}{2}}\)
- D \(\lambda \propto \mathrm{E}^{-\frac{1}{2}}\)
Answer & Solution
Correct Answer
(D) \(\lambda \propto \mathrm{E}^{-\frac{1}{2}}\)
Step-by-step Solution
Detailed explanation
De-Broglie wavelength, \(\lambda=\frac{\mathrm{h}}{\sqrt{2 \mathrm{mE}}}\) \(\therefore \quad \lambda \propto \mathrm{E}^{-\frac{1}{2}}\)
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