MHT CET · Physics · Dual Nature of Matter
The de-Broglie wavelength of a neutron at \(27^{\circ} \mathrm{C}\) is ' \(\lambda_0\) '. What will be its wavelength at \(927^{\circ} \mathrm{C}\) ?
- A \(\frac{\lambda_0}{4}\)
- B \(\frac{\lambda_0}{3}\)
- C \(\frac{\lambda_0}{2}\)
- D \(\frac{3 \lambda_0}{2}\)
Answer & Solution
Correct Answer
(C) \(\frac{\lambda_0}{2}\)
Step-by-step Solution
Detailed explanation
\( T_1 = 27 + 273 = 300 \, \mathrm{K} \) \( T_2 = 927 + 273 = 1200 \, \mathrm{K} \)
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