MHT CET · Physics · Oscillations
The damping force of an oscillator is directly proportional to the velocity. The unit of constant of proportionality is
- A \(\mathrm{kg} \mathrm{m} \mathrm{s}^{-2}\)
- B \(\mathrm{~kg} \mathrm{~s}^{-1}\)
- C \(\mathrm{~kg} \mathrm{~m} \mathrm{~s}^{-1}\)
- D \(\mathrm{~kg} \mathrm{~s}\)
Answer & Solution
Correct Answer
(B) \(\mathrm{~kg} \mathrm{~s}^{-1}\)
Step-by-step Solution
Detailed explanation
(D)
\(\begin{array}{l}
\mathrm{F}=\mathrm{bv} \\
\mathrm{b}=\frac{\mathrm{F}}{\mathrm{v}}=\frac{\mathrm{N}}{\mathrm{m} / \mathrm{s}}=\frac{\mathrm{MLT}^{-2}}{\mathrm{~L}} \mathrm{~T}=\mathrm{ML}^{-1} \\
\Rightarrow \mathrm{kg} \mathrm{sec}^{-1}
\end{array}\)
\(\begin{array}{l}
\mathrm{F}=\mathrm{bv} \\
\mathrm{b}=\frac{\mathrm{F}}{\mathrm{v}}=\frac{\mathrm{N}}{\mathrm{m} / \mathrm{s}}=\frac{\mathrm{MLT}^{-2}}{\mathrm{~L}} \mathrm{~T}=\mathrm{ML}^{-1} \\
\Rightarrow \mathrm{kg} \mathrm{sec}^{-1}
\end{array}\)
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