MHT CET · Physics · Current Electricity
The current drawn from the battery in the give network is (Internal resistance of the battery is negligible)
- A 2.4 A
- B 1.6 A
- C 2.0 A
- D 3.0 A
Answer & Solution
Correct Answer
(A) 2.4 A
Step-by-step Solution
Detailed explanation
It is a balanced Wheatstone bridge. No current will flow through \(5 \Omega\) resistance, and hence it can be removed from the circuit. \(3 \Omega\) and \(2 \Omega\) resistance are in series. Hence we have two branches with \(5 \Omega\) resistances each, connected in parallel. Their equivalent resistance \(2.5 \Omega\)
\(\therefore \mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}}=\frac{6}{2.5}=2.4 \mathrm{~A}\)
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