MHT CET · Physics · Electromagnetic Induction
The coefficient of mutual induction is 2 H and induced e.m.f. across secondary is 2 kV . Current in the primary is reduced from 6 A to 3 A . The time required for the change of current is
- A \(3 \times 10^{-3} \mathrm{~s}\)
- B \(3 \times 10^{-2} \mathrm{~s}\)
- C \(6 \times 10^{-3} \mathrm{~s}\)
- D \(3 \times 10^{-2} \mathrm{~s}\)
Answer & Solution
Correct Answer
(A) \(3 \times 10^{-3} \mathrm{~s}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} e_s & =M \cdot \frac{d I_p}{d t} \\ \therefore \quad d t & =M \cdot \frac{d I_p}{e_s} \\ \therefore \quad d t & =2 \times \frac{6-3}{2 \times 10^3}=3 \times 10^{-3} s\end{aligned}\)
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