MHT CET · Physics · Capacitance
The capacity of air filled parallel plate capacitor is \(\mathrm{C}_0\). One-half of the space between the plates is filled with a dielectric constant ' \(K\) ' as shown in figure. The new capacity becomes \(C_n\). The ratio \(C_n\) to \(C_0\) is
- A \(\left(\frac{\mathrm{K}+1}{2}\right)\)
- B \(\left(\frac{\mathrm{K}+1}{3}\right)\)
- C \(\left(\frac{\mathrm{K}+1}{4}\right)\)
- D 4(K+1)
Answer & Solution
Correct Answer
(A) \(\left(\frac{\mathrm{K}+1}{2}\right)\)
Step-by-step Solution
Detailed explanation
Initial capacity: \(C_0 = \frac{\epsilon_0 A}{d}\) Capacitor with air: \(C_1 = \frac{\epsilon_0 (A/2)}{d} = \frac{1}{2} C_0\)
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