MHT CET · Physics · Semiconductors
The Boolean expression for two-input Ex-OR gate is (A, B are inputs, Y is output)
- A \(Y=(\bar{A}+B) \cdot(A+\bar{B})\)
- B \(\mathrm{Y}=(\mathrm{A}, \mathrm{B})+(\overline{\mathrm{A}}+\overline{\mathrm{B}})\)
- C \(\mathrm{Y}=(\overline{\mathrm{A}} \cdot \mathrm{B})+(\mathrm{A} \cdot \overline{\mathrm{B}})\)
- D \(\mathrm{Y}=(\mathrm{A} \cdot \mathrm{B})+(\overline{\mathrm{A}}+\mathrm{B})\)
Answer & Solution
Correct Answer
(C) \(\mathrm{Y}=(\overline{\mathrm{A}} \cdot \mathrm{B})+(\mathrm{A} \cdot \overline{\mathrm{B}})\)
Step-by-step Solution
Detailed explanation
Truth table

Output equation: \(\mathrm{Y}=\mathrm{A} \oplus \mathrm{B}=(\overline{\mathrm{A}} \cdot \mathrm{B})+(\mathrm{A} \cdot \overline{\mathrm{B}})\)
Key points to remember:
(1) the output is low when both the inputs are the same
(2) the output is high when both the inputs are different

Output equation: \(\mathrm{Y}=\mathrm{A} \oplus \mathrm{B}=(\overline{\mathrm{A}} \cdot \mathrm{B})+(\mathrm{A} \cdot \overline{\mathrm{B}})\)
Key points to remember:
(1) the output is low when both the inputs are the same
(2) the output is high when both the inputs are different
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