MHT CET · Physics · Electromagnetic Induction
The area of a coil is 'A'. The coil is placed in a magnetic field which changes from \({ }^{\prime} \mathrm{B}_{0^{\prime}}\) to \({ }^{\circ} 4 \mathrm{~B}_{0}{ }^{\prime}\) in time \({ }^{\prime} \mathrm{t}^{\prime}\). The magnitude of induced e.m.f. in the coil will be
- A \(\frac{3 \mathrm{AB}_{0}}{\mathrm{t}}\)
- B \(\frac{4 \mathrm{AB}_{0}}{\mathrm{t}}\)
- C \(\frac{3 \mathrm{~B}_{0}}{\mathrm{At}}\)
- D \(\frac{4 \mathrm{~B}_{0}}{\mathrm{At}}\)
Answer & Solution
Correct Answer
(A) \(\frac{3 \mathrm{AB}_{0}}{\mathrm{t}}\)
Step-by-step Solution
Detailed explanation
\(\frac{\mathrm{dB}}{\mathrm{dt}}=\frac{\mathrm{d}}{\mathrm{dt}}\left(4 \mathrm{B}_{0}-\mathrm{B}_{0}\right)=\frac{3 \mathrm{~B}_{0}}{\mathrm{t}}\)
\(e=\frac{d \phi}{d t}=\frac{d}{d t} A \cdot 3 B_{0}=\frac{3 B_{0} A}{t}\)
\(e=\frac{d \phi}{d t}=\frac{d}{d t} A \cdot 3 B_{0}=\frac{3 B_{0} A}{t}\)
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