MHT CET · Physics · Waves and Sound
The apparent wavelength of light from a star moving away from the earth is \(0.02 \%\) more than the actual wavelength. The velocity of star is \(\left[\mathrm{c}=\right.\) velocity of light \(\left.=3 \times 10^8 \mathrm{~m} / \mathrm{s}\right]\)
- A \(30 \mathrm{~km} / \mathrm{s}\)
- B \(60 \mathrm{~km} / \mathrm{s}\)
- C \(90 \mathrm{~km} / \mathrm{s}\)
- D \(120 \mathrm{~km} / \mathrm{s}\)
Answer & Solution
Correct Answer
(B) \(60 \mathrm{~km} / \mathrm{s}\)
Step-by-step Solution
Detailed explanation
\(\frac{\Delta\lambda}{\lambda} = 0.02 \% = 0.0002\) \(v = c \frac{\Delta\lambda}{\lambda}\)
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