MHT CET · Physics · Motion In Two Dimensions
The angular displacement of body performing circular motion is given by \(\theta=5 \sin \frac{\pi t}{6}\). The angular velocity of the body at \(t=3\) second will be \(\left[\sin \frac{\pi}{2}=1, \cos \frac{\pi}{2}=0\right]\)
- A \(5 \frac{\mathrm{rad}}{\mathrm{s}}\)
- B \(1 \frac{\mathrm{rad}}{\mathrm{s}}\)
- C \(2.5 \frac{\mathrm{rad}}{\mathrm{s}}\)
- D zero
Answer & Solution
Correct Answer
(D) zero
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \theta=5 \sin \frac{\pi t}{6} \\ & \therefore \frac{\mathrm{d} \theta}{\mathrm{dt}}=\frac{\pi}{6} \cdot 5 \cos \frac{\pi \mathrm{t}}{6} \\ & \text { At } \mathrm{t}=3 \mathrm{~s}, \frac{\mathrm{d} \theta}{\mathrm{dt}}=\frac{5 \pi}{6} \cos \frac{\pi \times 3}{6}=\frac{5 \pi}{6} \cos \frac{\pi}{2}=0\end{aligned}\)
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