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MHT CET · Physics · Mechanical Properties of Fluids

The amount of work done in blowing a sops bubble such that its diameter increases from ' \(d\) ' to \(\mathrm{D}\) ' is ( \(\mathrm{T}\) = surface tension of solution )

  1. A \(4 \pi\left(D^2-d^2\right) T\)
  2. B \(8 \pi\left(D^2-d^2\right) T\)
  3. C \(\pi\left(D^2-d^2\right) T\)
  4. D \(2 \pi\left(D^2-d^2\right) T\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(2 \pi\left(D^2-d^2\right) T\)

Step-by-step Solution

Detailed explanation

Change in surface area
\(\begin{aligned} & =2 \times 4 \pi\left[\left(\frac{\mathrm{D}}{2}\right)^2-\left(\frac{\mathrm{d}}{2}\right)^2\right]=2 \pi\left(\mathrm{D}^2-\mathrm{d}^2\right) \\ & \therefore \text { Work done }=\text { surface tension } \times \text { change in area } \\ & =2 \pi\left(\mathrm{D}^2-\mathrm{d}^2\right) \mathrm{T}\end{aligned}\)