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MHT CET · Physics · Waves and Sound

Sound waves of frequency \(600 \mathrm{~Hz}\) fall normally on a perfectly reflecting wall. The shortest distance from the wall at which all particles will have maximum amplitude of vibration is (speed of sound \(=300 \mathrm{~ms}^{-1}\) )

  1. A \(\frac{1}{4} \mathrm{~m}\)
  2. B \(\frac{1}{8} \mathrm{~m}\)
  3. C \(\frac{3}{8} \mathrm{~m}\)
  4. D \(\frac{7}{8} \mathrm{~m}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{1}{8} \mathrm{~m}\)

Step-by-step Solution

Detailed explanation

The maximum displacement of the wave will occur at antinode of the wave. The first antinode will be a point where, \(\mathrm{d}=\frac{\lambda}{4}\)
The wavelength is given by,
\(\lambda=\frac{\mathrm{v}}{\mathrm{f}}=\frac{300}{600}\)
So, \(d=\frac{0.5}{4}=\frac{1}{8} m\)
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