MHT CET · Physics · Wave Optics
Sodium light \(\left(\lambda=6 \times 10^{-7} \mathrm{~m}\right)\) is used to produce interference pattern. The observed fringe width is 0.12 mm . The angle between the two wave trains is
- A \(5 \times 10^{-1} \mathrm{rad}\)
- B \(5 \times 10^{-3} \mathrm{rad}\)
- C \(1 \times 10^{-2} \mathrm{rad}\)
- D \(1 \times 10^{-3} \mathrm{rad}\)
Answer & Solution
Correct Answer
(B) \(5 \times 10^{-3} \mathrm{rad}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{W}=\frac{\lambda \mathrm{D}}{\mathrm{~d}}\)
Angle between the two wave trains is
\(\begin{aligned}
\frac{d}{D} & =\frac{\lambda}{W} \\
& =\frac{6 \times 10^{-7}}{0.12 \times 10^{-3}} \\
& =5 \times 10^{-3} \mathrm{rad}
\end{aligned}\)
Angle between the two wave trains is
\(\begin{aligned}
\frac{d}{D} & =\frac{\lambda}{W} \\
& =\frac{6 \times 10^{-7}}{0.12 \times 10^{-3}} \\
& =5 \times 10^{-3} \mathrm{rad}
\end{aligned}\)
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