MHT CET · Physics · Ray Optics
Refractive index of a glass convex lens is \(1 \cdot 5\). The radius of curvature of each of the two surfaces of the lens is 40 cm . The ratio of the power of the lens when immersed in a liquid of refractive index 1.25 to that when placed in air is
- A 2:3
- B 3:2
- C 2:5
- D 5:2
Answer & Solution
Correct Answer
(C) 2:5
Step-by-step Solution
Detailed explanation
\( \frac{P_l}{P_a} = \frac{\left(\frac{\mu_g}{\mu_l} - 1\right)}{\left(\frac{\mu_g}{\mu_a} - 1\right)} \) \( = \frac{\left(\frac{1.5}{1.25} - 1\right)}{\left(\frac{1.5}{1} - 1\right)} = \frac{(1.2 - 1)}{(1.5 - 1)} = \frac{0.2}{0.5} = \frac{2}{5} \)
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