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MHT CET · Physics · Current Electricity

Potentiometer wire is \(4 \mathrm{~m}\) long and potential difference of \(3 \mathrm{~V}\) is maintained between the ends. The e.m.f. of the cell which balances against a length of \(100 \mathrm{~cm}\) of the potentiometer wire is

  1. A 0.60 V
  2. B 0.20 V
  3. C 0.45 V
  4. D 0.75 V
Verified Solution

Answer & Solution

Correct Answer

(D) 0.75 V

Step-by-step Solution

Detailed explanation

Potential gradient \(=\frac{3}{4} \frac{\mathrm{V}}{\mathrm{m}}\)
So, emf against \(100 \mathrm{~cm}=\frac{3}{4} \times 1 \mathrm{~V}=0.75 \mathrm{~V}\)
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