MHT CET · Physics · Dual Nature of Matter
Photoemission from metal surface take place for frequencies ' \(v 1\) ' and ' \(v_2\) ' of incident rays. If ratio of maximum kinetic energy of photoelectrons is \(1: \mathrm{K}\) then threshold frequency of metallic surface is
- A \(\frac{\mathrm{K} v_2-v_1}{\mathrm{~K}-1}\)
- B \(\frac{v_1-v_2}{\mathrm{~K}-1}\)
- C \(\frac{v_2-v_1}{\mathrm{~K}}\)
- D \(\frac{\mathrm{K} v_1-v_2}{\mathrm{~K}-1}\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{K} v_1-v_2}{\mathrm{~K}-1}\)
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