MHT CET · Physics · Dual Nature of Matter
Photoelectrons are emitted when photons of energy \(4.2 \mathrm{eV}\) are incident on a photosensitive metallic sphere of radius \(10 \mathrm{~cm}\) and work function \(2.4 \mathrm{eV}\). The number of photoelectrons emitted before the emission is stopped is
\(
\left[\frac{1}{4 \pi \epsilon_0}=9 \times 10^9 \text { SI unit; } \mathrm{e}=1.6 \times 10^{-19} \mathrm{C}\right]
\)
- A \(1.25 \times 10^6\)
- B \(1.25 \times 10^8\)
- C \(1.25 \times 10^2\)
- D \(1.25 \times 10^4\)
Answer & Solution
Correct Answer
(B) \(1.25 \times 10^8\)
Step-by-step Solution
Detailed explanation
\(
\mathrm{h} v=4.2 \mathrm{eV}, \phi=2.4 \mathrm{eV},(\mathrm{KE})_{\max }=4.2-2.4\) \(=1.8 \mathrm{eV}
\)
The electrons will not be able to escape from the surface when its potential becomes \(1.8 \mathrm{~V}\).
\(
\begin{aligned}
& \mathrm{V}=\frac{1}{4 \pi \epsilon_0} \frac{\mathrm{q}}{\mathrm{r}} \\
& 1.8=9 \times 10^9 \times \frac{\mathrm{q}}{0.1} \\
& \mathrm{q}=2 \times 10^{-11} \mathrm{C}
\end{aligned}
\)
The number of photoelectrons emitted before the emission is stopped is,
\(
\mathrm{n}=\frac{\mathrm{q}}{\mathrm{e}}=\frac{2 \times 10^{-11}}{1.6 \times 10^{-19}}=1.25 \times 10^8
\)
\mathrm{h} v=4.2 \mathrm{eV}, \phi=2.4 \mathrm{eV},(\mathrm{KE})_{\max }=4.2-2.4\) \(=1.8 \mathrm{eV}
\)
The electrons will not be able to escape from the surface when its potential becomes \(1.8 \mathrm{~V}\).
\(
\begin{aligned}
& \mathrm{V}=\frac{1}{4 \pi \epsilon_0} \frac{\mathrm{q}}{\mathrm{r}} \\
& 1.8=9 \times 10^9 \times \frac{\mathrm{q}}{0.1} \\
& \mathrm{q}=2 \times 10^{-11} \mathrm{C}
\end{aligned}
\)
The number of photoelectrons emitted before the emission is stopped is,
\(
\mathrm{n}=\frac{\mathrm{q}}{\mathrm{e}}=\frac{2 \times 10^{-11}}{1.6 \times 10^{-19}}=1.25 \times 10^8
\)
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