MHT CET · Physics · Dual Nature of Matter
Photoelectric emission is observed from a metallic surface for frequencies \(v_1\) and \(v_2\) of the incident light rays ( \(v_1>v_2\) ). If the maximum values of kinetic energy of the photoelectrons emitted in the two cases are in the ratio of \(1: \mathrm{k}\), then the threshold frequency of metallic surface is
- A \(\frac{\mathrm{k} v_2-v_1}{\mathrm{k}-1}\)
- B \(\frac{v_2-v_1}{\mathrm{k}}\)
- C \(\frac{v_1-v_2}{\mathrm{k}-1}\)
- D \(\frac{\mathrm{k} v_1-v_2}{\mathrm{k}-1}\)
Answer & Solution
Correct Answer
(D) \(\frac{\mathrm{k} v_1-v_2}{\mathrm{k}-1}\)
Step-by-step Solution
Detailed explanation
\(K_1 = h\nu_1 - h\nu_0\) \(K_2 = h\nu_2 - h\nu_0\)
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