MHT CET · Physics · Ray Optics
Optical path of a particular ray of light has travelled a distance of 3 cm in flint glass is same as that on travelling a distance ' \(x\) ' cm through another medium. The value of ' \(x\) ' is [refractive index of flint glass \(=1 \cdot 6\), refractive index of another medium \(=1.25\) ]
- A 3.84 cm
- B 2.84 cm
- C 1.84 cm
- D 4.84 cm
Answer & Solution
Correct Answer
(A) 3.84 cm
Step-by-step Solution
Detailed explanation
As optical paths are equal,
\(\begin{aligned}
& \mu_{\mathrm{g}} \mathrm{x}_{\mathrm{g}}=\mu_{\mathrm{m}} \mathrm{x}_{\mathrm{m}} \\
& \mathrm{x}_{\mathrm{m}}=\frac{\mu_{\mathrm{g}} \mathrm{x}_{\mathrm{g}}}{\mu_{\mathrm{m}}}=\frac{1.6 \times 3}{1.25}=3.84 \mathrm{~cm}
\end{aligned}\)
\(\begin{aligned}
& \mu_{\mathrm{g}} \mathrm{x}_{\mathrm{g}}=\mu_{\mathrm{m}} \mathrm{x}_{\mathrm{m}} \\
& \mathrm{x}_{\mathrm{m}}=\frac{\mu_{\mathrm{g}} \mathrm{x}_{\mathrm{g}}}{\mu_{\mathrm{m}}}=\frac{1.6 \times 3}{1.25}=3.84 \mathrm{~cm}
\end{aligned}\)
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