MHT CET · Physics · Current Electricity
Only \(4 \%\) of the total current in the circuit passes through a galvanometer. If the resistance of the galvanometer is G , then the shunt resistance connected to the galvanometer is
- A \(\frac{G}{25}\)
- B \(\frac{\mathrm{G}}{24}\)
- C 24 G
- D 25 G
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{G}}{24}\)
Step-by-step Solution
Detailed explanation
\(I_g G = I_s S\) \(0.04 I \cdot G = (I - 0.04 I) S\)
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