MHT CET · Physics · Thermodynamics
One mole of an ideal gas expands adiabatically at constant pressure such that its temperature \(\mathrm{T} \propto \frac{1}{\sqrt{\mathrm{V}}}\). The value of \(\gamma\) for the gas is \((\gamma=\frac{C_p}{C_v}, V=\) Volumeof thegas\()\)
- A 1.8
- B 1.5
- C 1.3
- D 1.4
Answer & Solution
Correct Answer
(B) 1.5
Step-by-step Solution
Detailed explanation
For an adiabatic process at constant pressure, we have
\(\mathrm{TV}^{\gamma-1}=\text { constant }\)
Given, \(\mathrm{TV}^{1 / 2}=\) constant
Hence, \(\gamma-1=\frac{1}{2} \quad\) or \(\quad \gamma=1.5\)
\(\mathrm{TV}^{\gamma-1}=\text { constant }\)
Given, \(\mathrm{TV}^{1 / 2}=\) constant
Hence, \(\gamma-1=\frac{1}{2} \quad\) or \(\quad \gamma=1.5\)
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