MHT CET · Physics · Rotational Motion
Moment of inertia of a solid sphere about its diameter is 'I'. It is then casted into 27 small spheres of same diameter. The moment of inertia of each new sphere is
- A \(\frac{\text { I }}{243}\)
- B \(\frac{\text { I }}{122}\)
- C \(\frac{\mathrm{I}}{31}\)
- D \(\frac{\mathrm{I}}{62}\)
Answer & Solution
Correct Answer
(A) \(\frac{\text { I }}{243}\)
Step-by-step Solution
Detailed explanation
\(I = \frac{2}{5}MR^2\) \(M_{total} = 27m \Rightarrow M = 27m\)
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