MHT CET · Physics · Rotational Motion
Moment of inertia of a rod of mass \(M\) and length \(L\) about an axis passing through a point midway between centre and end is
- A \(\frac{M L^{2}}{6}\)
- B \(\frac{M L^{2}}{12}\)
- C \(\frac{7 M L^{2}}{24}\)
- D \(\frac{7 M L^{2}}{48}\)
Answer & Solution
Correct Answer
(D) \(\frac{7 M L^{2}}{48}\)
Step-by-step Solution
Detailed explanation
\(\begin{array}{l}=\frac{M L^{2}}{12}+M\left[\frac{L}{4}\right]^{2} \\=\frac{M L^{2}}{12}+\frac{M L^{2}}{16}=\frac{7 M L^{2}}{48}
\end{array}\)
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