MHT CET · Physics · Motion In Two Dimensions
Mass of \(0.5 \mathrm{~kg}\) is attached to a string moving in horizontal circle with angular velocity 10 cycle/min. Keeping the radius constant, tension in the string is made 4 times by increasing angular velocity '\(\omega\)'. The value ' \(\omega\) ' of that mass will be
- A \(\frac{1}{3}\) cycle \(/ \mathrm{s}\)
- B \(\frac{1}{2}\) cycle \(/ \mathrm{s}\)
- C \(\frac{1}{5}\) cycle \(/ \mathrm{s}\)
- D \(\frac{1}{4}\) cycle \(/ \mathrm{s}\)
Answer & Solution
Correct Answer
(A) \(\frac{1}{3}\) cycle \(/ \mathrm{s}\)
Step-by-step Solution
Detailed explanation
\(T = m r \omega^2\) \(T_2 = 4 T_1 \Rightarrow m r \omega_2^2 = 4 (m r \omega_1^2)\)
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