MHT CET · Physics · Wave Optics

Light of wavelength ' \(\lambda\) ' is incident on a slit of width 'd'. The resulting diffraction pattern is observed on a screen at a distance 'D'. The linear width of the principal maximum is then equal to the width of the slit if \(D\) equals

A \(\frac{\mathrm{d}}{\lambda}\)
B \(\frac{\mathrm{d}^2}{2 \lambda}\)
C \(\frac{2 \lambda}{\mathrm{d}}\)
D \(\frac{2 \lambda^2}{\mathrm{~d}}\)

Verified Solution

Answer & Solution

Correct Answer

(B) \(\frac{\mathrm{d}^2}{2 \lambda}\)

Step-by-step Solution

Detailed explanation

In diffraction of light by single slit, the width of central maximum is given as
\(\mathrm{W}_{\mathrm{c}}=\frac{2 \lambda \mathrm{D}}{\mathrm{d}}\)
Given: \(\mathrm{W}_{\mathrm{c}}=\mathrm{d}\)
\(\begin{aligned}
\therefore \quad d & =\frac{2 \lambda D}{d} \\
& \Rightarrow D=\frac{d^2}{2 \lambda}
\end{aligned}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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