MHT CET · Physics · Current Electricity
Let \(A\) be the cross-sectional area and \(\rho\) be the specific resistance of a potentiometer wire. If \(I\) is the current passing through the wire, then the potential gradient along the length of the wire is
- A \(\frac{I}{\rho A}\)
- B \(\frac{I A}{\rho}\)
- C \(I A \rho\)
- D \(\frac{I \rho}{A}\)
Answer & Solution
Correct Answer
(D) \(\frac{I \rho}{A}\)
Step-by-step Solution
Detailed explanation
Potential gradient \(=\) Potential difference per unit length . So,
\(k=\frac{V}{L}=\frac{I R}{L}=\frac{I(\rho L / A)}{L}=\frac{I \rho}{A}\)
\(k=\frac{V}{L}=\frac{I R}{L}=\frac{I(\rho L / A)}{L}=\frac{I \rho}{A}\)
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