MHT CET · Physics · Thermodynamics
Internal energy of \(\mathrm{n}_1\) moles of hydrogen at temperature ' \(\mathrm{T}\) ' is equal to internal energy of ' \(n_2\) ' moles of helium at temperature \(2 T\), then the ratio \(n_1: n_2\) is [Degree of freedom of \(\mathrm{He}=3\), Degree of freedom of \(\mathrm{H}_2=5\) ]
- A 5:3
- B 6:5
- C 2:3
- D 3:5
Answer & Solution
Correct Answer
(B) 6:5
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{n}_1 \frac{5}{2} \mathrm{RT}=\mathrm{n}_2 \frac{3}{2} \mathrm{R}(2 \mathrm{~T}) \\ & \therefore \frac{\mathrm{n}_1}{\mathrm{n}_2}=\frac{6}{5}\end{aligned}\)
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