MHT CET · Physics · Wave Optics
Interference fringes are produced on the screen by using two light sources of intensities I and 9I. The phase difference between the beams is \(\pi / 2\) at point \(P\) and \(\pi\) at point \(Q\) on the screen. The difference between the resultant intensities at points \(P\) and \(Q\) is \(\left(\cos 90^{\circ}=0, \cos \pi=-1\right)\)
- A 2 I
- B 4 I
- C 6 I
- D 8 I
Answer & Solution
Correct Answer
(C) 6 I
Step-by-step Solution
Detailed explanation
\(I_{res} = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi\) \(I_P = I + 9I + 2\sqrt{I \cdot 9I} \cos(\pi/2) = 10I + 2(3I)(0) = 10I\)
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