MHT CET · Physics · Capacitance
Initially n identical capacitors are joined in parallel and are charged to potential V. Now they are separated and joined in series. Then
- A potential difference and total energy of the combination remain the same.
- B potential difference remains the same and energy increases \(n\) times.
- C potential difference becomes nV and energy remains the same.
- D potential difference is nV and energy increases n times.
Answer & Solution
Correct Answer
(C) potential difference becomes nV and energy remains the same.
Step-by-step Solution
Detailed explanation
Charge on each capacitor: \( q = CV \) Potential difference across series combination: \( V_{series} = n \left( \frac{q}{C} \right) = n \left( \frac{CV}{C} \right) = nV \)
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