MHT CET · Physics · Capacitance
Initially \(n\) identical capacitors are joined in parallel and are charged to potential \(V\). Now they are separated and joined in series. Then
- A Potential difference becomes \(n V\) and energy remains the same.
- B potential difference is \(n V\) and energy increases \(n\) times
- C potential difference total energy of combination remains same
- D potential difference remains the same and the energy increases \(n\) times.
Answer & Solution
Correct Answer
(A) Potential difference becomes \(n V\) and energy remains the same.
Step-by-step Solution
Detailed explanation
Charge will not flow and potential difference across each capacitor will be \(V\). Hence, total potential difference across the series combination will be \(n V\).
Total energy will remain same as charge is not flowing.
Total energy will remain same as charge is not flowing.
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